sort a file, spaces to new line

[Burke]

hi

i have a file with names like:

Code: Select all

name1 name2  name3     name4
name 5 name6  name6
  name8 name9 name10  name11 name 11

i want to remove the spaces. for every space, a new line.

how to set a var to my paste here i know. (open file etc.)
or how i can close file and save.

but i have no idea which commands will help me to make the " " or " " to a new line.

[demond]

Code: Select all

string map {" " "\n"} "name1 name2"

or, better yet

Code: Select all

regsub -all " {1,}" [string trim "  name1 name2   name3 "] "\n"

[De Kus]

trim will only remove leading and trailing spaces, best will probably be if you first just [split $list] and then you will get a few empty list entrys which can be delted within a for loop and lreplace and all left is a clean, safe list of the names.

to show what split does:

Code: Select all

[14:15:03] tcl: evaluate (.tcl): split "name1   name2\nname3"
Tcl: name1 {} {} name2 name3

[demond]

trim will only remove leading and trailing spaces, best will probably be if you first just [split $list] and then you will get a few empty list entrys which can be delted within a for loop and lreplace and all left is a clean, safe list of the names.

to show what split does:

Code: Select all

[14:15:03] tcl: evaluate (.tcl): split "name1   name2\nname3"
Tcl: name1 {} {} name2 name3

you didn't bother to test that regsub, did you?

it takes care of arbitrary number of spaces in-between, and [string trim] takes care of leading and trailing spaces - just what that guy needs, nothing more, nothing less

[De Kus]

sorry, didnt pay too much attention to the " {1,}" expression, since it never worked that way I liked . my regsubs with RE never replaced anything . but this one works, sorry for bother.